(m+4)(m+1)=

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Solution for (m+4)(m+1)= equation:


Simplifying
(m + 4)(m + 1) = 0

Reorder the terms:
(4 + m)(m + 1) = 0

Reorder the terms:
(4 + m)(1 + m) = 0

Multiply (4 + m) * (1 + m)
(4(1 + m) + m(1 + m)) = 0
((1 * 4 + m * 4) + m(1 + m)) = 0
((4 + 4m) + m(1 + m)) = 0
(4 + 4m + (1 * m + m * m)) = 0
(4 + 4m + (1m + m2)) = 0

Combine like terms: 4m + 1m = 5m
(4 + 5m + m2) = 0

Solving
4 + 5m + m2 = 0

Solving for variable 'm'.

Factor a trinomial.
(4 + m)(1 + m) = 0

Subproblem 1

Set the factor '(4 + m)' equal to zero and attempt to solve: Simplifying 4 + m = 0 Solving 4 + m = 0 Move all terms containing m to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + m = 0 + -4 Combine like terms: 4 + -4 = 0 0 + m = 0 + -4 m = 0 + -4 Combine like terms: 0 + -4 = -4 m = -4 Simplifying m = -4

Subproblem 2

Set the factor '(1 + m)' equal to zero and attempt to solve: Simplifying 1 + m = 0 Solving 1 + m = 0 Move all terms containing m to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + m = 0 + -1 Combine like terms: 1 + -1 = 0 0 + m = 0 + -1 m = 0 + -1 Combine like terms: 0 + -1 = -1 m = -1 Simplifying m = -1

Solution

m = {-4, -1}

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