(m+5)/(m+1)=70/(m-4)(m+1)

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Solution for (m+5)/(m+1)=70/(m-4)(m+1) equation: 


D( m )

m-4 = 0

m+1 = 0

m-4 = 0

m-4 = 0

m-4 = 0 // + 4

m = 4

m+1 = 0

m+1 = 0

m+1 = 0 // - 1

m = -1

m in (-oo:-1) U (-1:4) U (4:+oo)

(m+5)/(m+1) = (70/(m-4))*(m+1) // - (70/(m-4))*(m+1)

(m+5)/(m+1)-((70/(m-4))*(m+1)) = 0

(m+5)/(m+1)-70*(m-4)^-1*(m+1) = 0

(m+5)/(m+1)+(-70*(m+1))/(m-4) = 0

((m+5)*(m-4))/((m+1)*(m-4))+(-70*(m+1)^2)/((m+1)*(m-4)) = 0

(m+5)*(m-4)-70*(m+1)^2 = 0

-69*m^2-139*m-90 = 0

-69*m^2-139*m-90 = 0

-1*(69*m^2+139*m+90) = 0

69*m^2+139*m+90 = 0

DELTA = 139^2-(4*69*90)

DELTA = -5519

DELTA < 0

-1 = 0

-1/((m+1)*(m-4)) = 0

-1/((m+1)*(m-4)) = 0 // * (m+1)*(m-4)

-1 = 0

m belongs to the empty set

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