(m+7)(m-3)=(m-4)(m+5)

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Solution for (m+7)(m-3)=(m-4)(m+5) equation: 



(m+7)(m-3)=(m-4)(m+5)

We move all terms to the left:

(m+7)(m-3)-((m-4)(m+5))=0

We multiply parentheses ..

(+m^2-3m+7m-21)-((m-4)(m+5))=0



We calculate terms in parentheses: -((m-4)(m+5)), so:

(m-4)(m+5)

We multiply parentheses ..

(+m^2+5m-4m-20)

We get rid of parentheses

m^2+5m-4m-20

We add all the numbers together, and all the variables

m^2+m-20

Back to the equation:

-(m^2+m-20)



We get rid of parentheses

m^2-m^2-3m+7m-m-21+20=0

We add all the numbers together, and all the variables

3m-1=0

We move all terms containing m to the left, all other terms to the right

3m=1

m=1/3

m=1/3

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