(m+8)(m+7)=m+56

Solution for (m+8)(m+7)=m+56 equation:

(m+8)(m+7)=m+56

We move all terms to the left:

(m+8)(m+7)-(m+56)=0

We get rid of parentheses

(m+8)(m+7)-m-56=0

We multiply parentheses ..

(+m^2+7m+8m+56)-m-56=0

We add all the numbers together, and all the variables

(+m^2+7m+8m+56)-1m-56=0

We get rid of parentheses

m^2+7m+8m-1m+56-56=0

We add all the numbers together, and all the variables

m^2+14m=0

a = 1; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·1·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*1}=\frac{-28}{2}
=-14
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*1}=\frac{0}{2}
=0
$