(m-1)(m-1)=

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Solution for (m-1)(m-1)= equation: 



(m-1)(m-1)=

We move all terms to the left:

(m-1)(m-1)-()=0

We add all the numbers together, and all the variables

(m-1)(m-1)=0

We multiply parentheses ..

(+m^2-1m-1m+1)=0

We get rid of parentheses

m^2-1m-1m+1=0

We add all the numbers together, and all the variables

m^2-2m+1=0

a = 1; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{2}{2}=1$

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