(m-11)(5m-4)=0

Solution for (m-11)(5m-4)=0 equation:

(m-11)(5m-4)=0

We multiply parentheses ..

(+5m^2-4m-55m+44)=0

We get rid of parentheses

5m^2-4m-55m+44=0

We add all the numbers together, and all the variables

5m^2-59m+44=0

a = 5; b = -59; c = +44;
Δ = b2-4ac
Δ = -592-4·5·44
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-51}{2*5}=\frac{8}{10}
=4/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+51}{2*5}=\frac{110}{10}
=11
$