(m-12)(8m-3)=0

Solution for (m-12)(8m-3)=0 equation:

(m-12)(8m-3)=0

We multiply parentheses ..

(+8m^2-3m-96m+36)=0

We get rid of parentheses

8m^2-3m-96m+36=0

We add all the numbers together, and all the variables

8m^2-99m+36=0

a = 8; b = -99; c = +36;
Δ = b2-4ac
Δ = -992-4·8·36
Δ = 8649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8649}=93$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-99)-93}{2*8}=\frac{6}{16}
=3/8
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-99)+93}{2*8}=\frac{192}{16}
=12
$