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(m-2)(m-2)=0
We multiply parentheses ..
(+m^2-2m-2m+4)=0
We get rid of parentheses
m^2-2m-2m+4=0
We add all the numbers together, and all the variables
m^2-4m+4=0
a = 1; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$m=\frac{-b}{2a}=\frac{4}{2}=2$
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