(m-3)(m+7)-(m+2)(m-8)=0

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Solution for (m-3)(m+7)-(m+2)(m-8)=0 equation:



(m-3)(m+7)-(m+2)(m-8)=0
We multiply parentheses ..
(+m^2+7m-3m-21)-(m+2)(m-8)=0
We get rid of parentheses
m^2+7m-3m-(m+2)(m-8)-21=0
We multiply parentheses ..
m^2-(+m^2-8m+2m-16)+7m-3m-21=0
We add all the numbers together, and all the variables
m^2-(+m^2-8m+2m-16)+4m-21=0
We get rid of parentheses
m^2-m^2+8m-2m+4m+16-21=0
We add all the numbers together, and all the variables
10m-5=0
We move all terms containing m to the left, all other terms to the right
10m=5
m=5/10
m=1/2

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