(m-3)+2m=3(m-1)

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Solution for (m-3)+2m=3(m-1) equation:


Simplifying
(m + -3) + 2m = 3(m + -1)

Reorder the terms:
(-3 + m) + 2m = 3(m + -1)

Remove parenthesis around (-3 + m)
-3 + m + 2m = 3(m + -1)

Combine like terms: m + 2m = 3m
-3 + 3m = 3(m + -1)

Reorder the terms:
-3 + 3m = 3(-1 + m)
-3 + 3m = (-1 * 3 + m * 3)
-3 + 3m = (-3 + 3m)

Add '3' to each side of the equation.
-3 + 3 + 3m = -3 + 3 + 3m

Combine like terms: -3 + 3 = 0
0 + 3m = -3 + 3 + 3m
3m = -3 + 3 + 3m

Combine like terms: -3 + 3 = 0
3m = 0 + 3m
3m = 3m

Add '-3m' to each side of the equation.
3m + -3m = 3m + -3m

Combine like terms: 3m + -3m = 0
0 = 3m + -3m

Combine like terms: 3m + -3m = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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