(m-8)(m+5)=14

Solution for (m-8)(m+5)=14 equation:

(m-8)(m+5)=14

We move all terms to the left:

(m-8)(m+5)-(14)=0

We multiply parentheses ..

(+m^2+5m-8m-40)-14=0

We get rid of parentheses

m^2+5m-8m-40-14=0

We add all the numbers together, and all the variables

m^2-3m-54=0

a = 1; b = -3; c = -54;
Δ = b2-4ac
Δ = -32-4·1·(-54)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-15}{2*1}=\frac{-12}{2}
=-6
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+15}{2*1}=\frac{18}{2}
=9
$