(m-8)(m-8)=0

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Solution for (m-8)(m-8)=0 equation: 



(m-8)(m-8)=0

We multiply parentheses ..

(+m^2-8m-8m+64)=0

We get rid of parentheses

m^2-8m-8m+64=0

We add all the numbers together, and all the variables

m^2-16m+64=0

a = 1; b = -16; c = +64;
Δ = b2-4ac
Δ = -162-4·1·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{16}{2}=8$

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