(m/18)=-(1/9)

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Solution for (m/18)=-(1/9) equation:



(m/18)=-(1/9)
We move all terms to the left:
(m/18)-(-(1/9))=0
We add all the numbers together, and all the variables
(+m/18)-(-(+1/9))=0
We get rid of parentheses
m/18-(-(+1/9))=0
We calculate fractions
9m^2/()+()/()=0
We add all the numbers together, and all the variables
9m^2/()+1=0
We multiply all the terms by the denominator
9m^2+1*()=0
We add all the numbers together, and all the variables
9m^2=0
a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{18}=0$

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