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(m2+16)=0
We add all the numbers together, and all the variables
(+m^2+16)=0
We get rid of parentheses
m^2+16=0
a = 1; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·1·16
Δ = -64
Delta is less than zero, so there is no solution for the equation
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