(n(n+1))/2=210

Solution for (n(n+1))/2=210 equation:

(n(n+1))/2=210

We move all terms to the left:

(n(n+1))/2-(210)=0

We multiply all the terms by the denominator


(n(n+1))-210*2=0


We calculate terms in parentheses: +(n(n+1)), so:

n(n+1)

We multiply parentheses

n^2+n

Back to the equation:

+(n^2+n)


We add all the numbers together, and all the variables

(n^2+n)-420=0

We get rid of parentheses

n^2+n-420=0

a = 1; b = 1; c = -420;
Δ = b2-4ac
Δ = 12-4·1·(-420)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-41}{2*1}=\frac{-42}{2}
=-21
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+41}{2*1}=\frac{40}{2}
=20
$