(n(n+1)/2)=(1000(1000+1)/2)

Solution for (n(n+1)/2)=(1000(1000+1)/2) equation:

(n(n+1)/2)=(1000(1000+1)/2)

We move all terms to the left:

(n(n+1)/2)-((1000(1000+1)/2))=0

We add all the numbers together, and all the variables

(n(n+1)/2)-((10001001/2))=0

We calculate fractions


3n^2/()+()/()=0

We add all the numbers together, and all the variables

3n^2/()+1=0

We multiply all the terms by the denominator


3n^2+1*()=0

We add all the numbers together, and all the variables

3n^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{6}=0$