(n(n-3)/2)=10n

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Solution for (n(n-3)/2)=10n equation: 



(n(n-3)/2)=10n

We move all terms to the left:

(n(n-3)/2)-(10n)=0

We add all the numbers together, and all the variables

-10n+(n(n-3)/2)=0

We multiply all the terms by the denominator


-10n*2)+(n(n-3)=0

Wy multiply elements

-20n^2=0

a = -20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-20)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{-40}=0$

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