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(n)/(n-12)=(9)/(5)
We move all terms to the left:
(n)/(n-12)-((9)/(5))=0
Domain of the equation: (n-12)!=0We add all the numbers together, and all the variables
We move all terms containing n to the left, all other terms to the right
n!=12
n∈R
n/(n-12)-(+9/5)=0
We get rid of parentheses
n/(n-12)-9/5=0
We calculate fractions
5n/(5n-60)+(-9n+108)/(5n-60)=0
We multiply all the terms by the denominator
5n+(-9n+108)=0
We get rid of parentheses
5n-9n+108=0
We add all the numbers together, and all the variables
-4n+108=0
We move all terms containing n to the left, all other terms to the right
-4n=-108
n=-108/-4
n=+27
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