(n)=n(n-3)(n-7)-n2(n-8)

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Solution for (n)=n(n-3)(n-7)-n2(n-8) equation: 



(n)=n(n-3)(n-7)-n2(n-8)

We move all terms to the left:

(n)-(n(n-3)(n-7)-n2(n-8))=0

We multiply parentheses ..

-(n(+n^2-7n-3n+21)-n2(n-8))+n=0



We calculate terms in parentheses: -(n(+n^2-7n-3n+21)-n2(n-8)), so:

n(+n^2-7n-3n+21)-n2(n-8)

We multiply parentheses

n^3-7n^2-3n^2-n^3+8n^2+21n

We do not support enpression: n^3

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