(n+0.3)/(n-3.2)=9/2

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Solution for (n+0.3)/(n-3.2)=9/2 equation: 



(n+0.3)/(n-3.2)=9/2

We move all terms to the left:

(n+0.3)/(n-3.2)-(9/2)=0



Domain of the equation: (n-3.2)!=0

We move all terms containing n to the left, all other terms to the right

n!=3.2

n∈R



We add all the numbers together, and all the variables

(n+0.3)/(n-3.2)-(+9/2)=0

We get rid of parentheses

(n+0.3)/(n-3.2)-9/2=0

We calculate fractions


(2n+0.6)/(2n-6.4)+(-9n+28.8)/(2n-6.4)=0

We multiply all the terms by the denominator


(2n+0.6)+(-9n+28.8)=0

We get rid of parentheses

2n-9n+0.6+28.8=0

We add all the numbers together, and all the variables

-7n+29.4=0

We move all terms containing n to the left, all other terms to the right

-7n=-29.4

n=-29.4/-7

n=4+1/5

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