(n+0.6+n)2=(n+0.1+2n)2

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Solution for (n+0.6+n)2=(n+0.1+2n)2 equation:



(n+0.6+n)2=(n+0.1+2n)2
We move all terms to the left:
(n+0.6+n)2-((n+0.1+2n)2)=0
We add all the numbers together, and all the variables
(2n+0.6)2-((3n+0.1)2)=0
We multiply parentheses
4n-((3n+0.1)2)+1.2=0
We calculate terms in parentheses: -((3n+0.1)2), so:
(3n+0.1)2
We multiply parentheses
6n+0.2
Back to the equation:
-(6n+0.2)
We get rid of parentheses
4n-6n-0.2+1.2=0
We add all the numbers together, and all the variables
-2n+1=0
We move all terms containing n to the left, all other terms to the right
-2n=-1
n=-1/-2
n=1/2

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