(n+1)(2n-5)=0

Solution for (n+1)(2n-5)=0 equation:

Simplifying
(n + 1)(2n + -5) = 0

Reorder the terms:
(1 + n)(2n + -5) = 0

Reorder the terms:
(1 + n)(-5 + 2n) = 0

Multiply (1 + n) * (-5 + 2n)
(1(-5 + 2n) + n(-5 + 2n)) = 0
((-5 * 1 + 2n * 1) + n(-5 + 2n)) = 0
((-5 + 2n) + n(-5 + 2n)) = 0
(-5 + 2n + (-5 * n + 2n * n)) = 0
(-5 + 2n + (-5n + 2n2)) = 0

Combine like terms: 2n + -5n = -3n
(-5 + -3n + 2n2) = 0

Solving
-5 + -3n + 2n2 = 0

Solving for variable 'n'.

Factor a trinomial.
(-1 + -1n)(5 + -2n) = 0

Subproblem 1
Set the factor '(-1 + -1n)' equal to zero and attempt to solve:

Simplifying
-1 + -1n = 0

Solving
-1 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1n = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1n = 0 + 1
-1n = 0 + 1

Combine like terms: 0 + 1 = 1
-1n = 1

Divide each side by '-1'.
n = -1

Simplifying
n = -1
Subproblem 2
Set the factor '(5 + -2n)' equal to zero and attempt to solve:

Simplifying
5 + -2n = 0

Solving
5 + -2n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -2n = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -2n = 0 + -5
-2n = 0 + -5

Combine like terms: 0 + -5 = -5
-2n = -5

Divide each side by '-2'.
n = 2.5

Simplifying
n = 2.5
Solution
n = {-1, 2.5}