(n+1)(n+2)(n+3)(n+4)=

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Solution for (n+1)(n+2)(n+3)(n+4)= equation: 



(n+1)(n+2)(n+3)(n+4)=

We move all terms to the left:

(n+1)(n+2)(n+3)(n+4)-()=0

We add all the numbers together, and all the variables

(n+1)(n+2)(n+3)(n+4)=0

We multiply parentheses ..

(+n^2+2n+n+2)(n+3)(n+4)=0

We multiply parentheses ..

(+n^2+2n+n+2)(+n^2+4n+3n+12)=0

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