(n+1)(n+2)(n+3)=336

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Solution for (n+1)(n+2)(n+3)=336 equation: 



(n+1)(n+2)(n+3)=336

We move all terms to the left:

(n+1)(n+2)(n+3)-(336)=0

We multiply parentheses ..

(+n^2+2n+n+2)(n+3)-336=0

We move all terms containing n to the left, all other terms to the right

(+n^2+2n+n+2)(n+3)=336

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