(n+1)*((n+1)-2)=60

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Solution for (n+1)*((n+1)-2)=60 equation:


Simplifying
(n + 1)((n + 1) + -2) = 60

Reorder the terms:
(1 + n)((n + 1) + -2) = 60

Reorder the terms:
(1 + n)((1 + n) + -2) = 60

Remove parenthesis around (1 + n)
(1 + n)(1 + n + -2) = 60

Reorder the terms:
(1 + n)(1 + -2 + n) = 60

Combine like terms: 1 + -2 = -1
(1 + n)(-1 + n) = 60

Multiply (1 + n) * (-1 + n)
(1(-1 + n) + n(-1 + n)) = 60
((-1 * 1 + n * 1) + n(-1 + n)) = 60
((-1 + 1n) + n(-1 + n)) = 60
(-1 + 1n + (-1 * n + n * n)) = 60
(-1 + 1n + (-1n + n2)) = 60

Combine like terms: 1n + -1n = 0
(-1 + 0 + n2) = 60
(-1 + n2) = 60

Solving
-1 + n2 = 60

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + n2 = 60 + 1

Combine like terms: -1 + 1 = 0
0 + n2 = 60 + 1
n2 = 60 + 1

Combine like terms: 60 + 1 = 61
n2 = 61

Simplifying
n2 = 61

Take the square root of each side:
n = {-7.810249676, 7.810249676}

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