(n+1)/3=(3n-5)/6

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Solution for (n+1)/3=(3n-5)/6 equation: 



(n+1)/3=(3n-5)/6

We move all terms to the left:

(n+1)/3-((3n-5)/6)=0

We calculate fractions


n/()+(-((3n-5)*3)/()=0



We calculate terms in parentheses: +(-((3n-5)*3)/(), so:

-((3n-5)*3)/(

We multiply all the terms by the denominator


-((3n-5)*3)



We calculate terms in parentheses: -((3n-5)*3), so:

(3n-5)*3

We multiply parentheses

9n-15

Back to the equation:

-(9n-15)



We get rid of parentheses

-9n+15

Back to the equation:

+(-9n+15)



We get rid of parentheses

n/()-9n+15=0

We multiply all the terms by the denominator


n-9n*()+15*()=0

We add all the numbers together, and all the variables

n-9n*()=0

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