(n+1/n-2)=(4/7)

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Solution for (n+1/n-2)=(4/7) equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

n+1/n-2 = 4/7 // - 4/7

n+1/n-(4/7)-2 = 0

n+1/n-4/7-2 = 0

1*n^1+1*n^-1-18/7*n^0 = 0

(1*n^2-18/7*n^1+1*n^0)/(n^1) = 0 // * n^2

n^1*(1*n^2-18/7*n^1+1*n^0) = 0

n^1

n^2+(-18/7)*n+1 = 0

n^2+(-18/7)*n+1 = 0

DELTA = (-18/7)^2-(1*1*4)

DELTA = 128/49

DELTA > 0

n = ((128/49)^(1/2)-(-18/7))/(1*2) or n = (-(-18/7)-(128/49)^(1/2))/(1*2)

n = ((128/49)^(1/2)+18/7)/2 or n = (18/7-(128/49)^(1/2))/2

n in { (18/7-(128/49)^(1/2))/2, ((128/49)^(1/2)+18/7)/2} 

n in { (18/7-(128/49)^(1/2))/2, ((128/49)^(1/2)+18/7)/2 }

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