(n+13)(n-2)=0

Solution for (n+13)(n-2)=0 equation:

(n+13)(n-2)=0

We multiply parentheses ..

(+n^2-2n+13n-26)=0

We get rid of parentheses

n^2-2n+13n-26=0

We add all the numbers together, and all the variables

n^2+11n-26=0

a = 1; b = 11; c = -26;
Δ = b2-4ac
Δ = 112-4·1·(-26)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-15}{2*1}=\frac{-26}{2}
=-13
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+15}{2*1}=\frac{4}{2}
=2
$