(n+18)+(n2)=180

Solution for (n+18)+(n2)=180 equation:

(+18)+(N2)=180

We move all terms to the left:

(+18)+(N2)-(180)=0

determiningTheFunctionDomain
N2-180+(+18)=0

We add all the numbers together, and all the variables

N2-180+18=0

We add all the numbers together, and all the variables

N^2-162=0

a = 1; b = 0; c = -162;
Δ = b2-4ac
Δ = 02-4·1·(-162)
Δ = 648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$N_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$N_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{648}=\sqrt{324*2}=\sqrt{324}*\sqrt{2}=18\sqrt{2}$
$N_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{2}}{2*1}=\frac{0-18\sqrt{2}}{2}
=-\frac{18\sqrt{2}}{2}
=-9\sqrt{2}
$
$N_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{2}}{2*1}=\frac{0+18\sqrt{2}}{2}
=\frac{18\sqrt{2}}{2}
=9\sqrt{2}
$