(n+2)(n+1)n(n-1)=360

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Solution for (n+2)(n+1)n(n-1)=360 equation: 



(n+2)(n+1)n(n-1)=360

We move all terms to the left:

(n+2)(n+1)n(n-1)-(360)=0

We multiply parentheses ..

(+n^2+n+2n+2)n(n-1)-360=0

We move all terms containing n to the left, all other terms to the right

(+n^2+n+2n+2)n(n-1)=360

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