(n+2)(n+5)=n

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Solution for (n+2)(n+5)=n equation: 



(n+2)(n+5)=n

We move all terms to the left:

(n+2)(n+5)-(n)=0

We add all the numbers together, and all the variables

-1n+(n+2)(n+5)=0

We multiply parentheses ..

(+n^2+5n+2n+10)-1n=0

We get rid of parentheses

n^2+5n+2n-1n+10=0

We add all the numbers together, and all the variables

n^2+6n+10=0

a = 1; b = 6; c = +10;
Δ = b2-4ac
Δ = 62-4·1·10
Δ = -4
Delta is less than zero, so there is no solution for the equation

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