(n+2)(n-2)=0

Solution for (n+2)(n-2)=0 equation:

Simplifying
(n + 2)(n + -2) = 0

Reorder the terms:
(2 + n)(n + -2) = 0

Reorder the terms:
(2 + n)(-2 + n) = 0

Multiply (2 + n) * (-2 + n)
(2(-2 + n) + n(-2 + n)) = 0
((-2 * 2 + n * 2) + n(-2 + n)) = 0
((-4 + 2n) + n(-2 + n)) = 0
(-4 + 2n + (-2 * n + n * n)) = 0
(-4 + 2n + (-2n + n2)) = 0

Combine like terms: 2n + -2n = 0
(-4 + 0 + n2) = 0
(-4 + n2) = 0

Solving
-4 + n2 = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + n2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + n2 = 0 + 4
n2 = 0 + 4

Combine like terms: 0 + 4 = 4
n2 = 4

Simplifying
n2 = 4

Take the square root of each side:
n = {-2, 2}