(n+3)(n+2)(n+1)=336

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Solution for (n+3)(n+2)(n+1)=336 equation:



(n+3)(n+2)(n+1)=336
We move all terms to the left:
(n+3)(n+2)(n+1)-(336)=0
We multiply parentheses ..
(+n^2+2n+3n+6)(n+1)-336=0
We move all terms containing n to the left, all other terms to the right
(+n^2+2n+3n+6)(n+1)=336

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