(n+3)(n+2)=

Solution for (n+3)(n+2)= equation:

Simplifying
(n + 3)(n + 2) = 0

Reorder the terms:
(3 + n)(n + 2) = 0

Reorder the terms:
(3 + n)(2 + n) = 0

Multiply (3 + n) * (2 + n)
(3(2 + n) + n(2 + n)) = 0
((2 * 3 + n * 3) + n(2 + n)) = 0
((6 + 3n) + n(2 + n)) = 0
(6 + 3n + (2 * n + n * n)) = 0
(6 + 3n + (2n + n2)) = 0

Combine like terms: 3n + 2n = 5n
(6 + 5n + n2) = 0

Solving
6 + 5n + n2 = 0

Solving for variable 'n'.

Factor a trinomial.
(3 + n)(2 + n) = 0

Subproblem 1
Set the factor '(3 + n)' equal to zero and attempt to solve:

Simplifying
3 + n = 0

Solving
3 + n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + n = 0 + -3

Combine like terms: 3 + -3 = 0
0 + n = 0 + -3
n = 0 + -3

Combine like terms: 0 + -3 = -3
n = -3

Simplifying
n = -3
Subproblem 2
Set the factor '(2 + n)' equal to zero and attempt to solve:

Simplifying
2 + n = 0

Solving
2 + n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + n = 0 + -2

Combine like terms: 2 + -2 = 0
0 + n = 0 + -2
n = 0 + -2

Combine like terms: 0 + -2 = -2
n = -2

Simplifying
n = -2
Solution
n = {-3, -2}