(n+3)(n+3)=0

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Solution for (n+3)(n+3)=0 equation: 



(n+3)(n+3)=0

We multiply parentheses ..

(+n^2+3n+3n+9)=0

We get rid of parentheses

n^2+3n+3n+9=0

We add all the numbers together, and all the variables

n^2+6n+9=0

a = 1; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-6}{2}=-3$

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