(n+3)(n-2)=0

Solution for (n+3)(n-2)=0 equation:

Simplifying
(n + 3)(n + -2) = 0

Reorder the terms:
(3 + n)(n + -2) = 0

Reorder the terms:
(3 + n)(-2 + n) = 0

Multiply (3 + n) * (-2 + n)
(3(-2 + n) + n(-2 + n)) = 0
((-2 * 3 + n * 3) + n(-2 + n)) = 0
((-6 + 3n) + n(-2 + n)) = 0
(-6 + 3n + (-2 * n + n * n)) = 0
(-6 + 3n + (-2n + n2)) = 0

Combine like terms: 3n + -2n = 1n
(-6 + 1n + n2) = 0

Solving
-6 + 1n + n2 = 0

Solving for variable 'n'.

Factor a trinomial.
(-3 + -1n)(2 + -1n) = 0

Subproblem 1
Set the factor '(-3 + -1n)' equal to zero and attempt to solve:

Simplifying
-3 + -1n = 0

Solving
-3 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -1n = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -1n = 0 + 3
-1n = 0 + 3

Combine like terms: 0 + 3 = 3
-1n = 3

Divide each side by '-1'.
n = -3

Simplifying
n = -3
Subproblem 2
Set the factor '(2 + -1n)' equal to zero and attempt to solve:

Simplifying
2 + -1n = 0

Solving
2 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1n = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1n = 0 + -2
-1n = 0 + -2

Combine like terms: 0 + -2 = -2
-1n = -2

Divide each side by '-1'.
n = 2

Simplifying
n = 2
Solution
n = {-3, 2}