(n+3)+2(n+3)=3

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Solution for (n+3)+2(n+3)=3 equation: 



(n+3)+2(n+3)=3

We move all terms to the left:

(n+3)+2(n+3)-(3)=0

We multiply parentheses

(n+3)+2n+6-3=0

We get rid of parentheses

n+2n+3+6-3=0

We add all the numbers together, and all the variables

3n+6=0

We move all terms containing n to the left, all other terms to the right

3n=-6

n=-6/3

n=-2

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