(n+3)/3=(n+5)/5

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Solution for (n+3)/3=(n+5)/5 equation: 



(n+3)/3=(n+5)/5

We move all terms to the left:

(n+3)/3-((n+5)/5)=0

We calculate fractions


n/()+(-((n+5)*3)/()=0



We calculate terms in parentheses: +(-((n+5)*3)/(), so:

-((n+5)*3)/(

We multiply all the terms by the denominator


-((n+5)*3)



We calculate terms in parentheses: -((n+5)*3), so:

(n+5)*3

We multiply parentheses

3n+15

Back to the equation:

-(3n+15)



We get rid of parentheses

-3n-15

Back to the equation:

+(-3n-15)



We get rid of parentheses

n/()-3n-15=0

We multiply all the terms by the denominator


n-3n*()-15*()=0

We add all the numbers together, and all the variables

n-3n*()=0

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