(n+3)/6=(2n-1)/9

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Solution for (n+3)/6=(2n-1)/9 equation:



(n+3)/6=(2n-1)/9
We move all terms to the left:
(n+3)/6-((2n-1)/9)=0
We calculate fractions
n/()+(-((2n-1)*6)/()=0
We calculate terms in parentheses: +(-((2n-1)*6)/(), so:
-((2n-1)*6)/(
We multiply all the terms by the denominator
-((2n-1)*6)
We calculate terms in parentheses: -((2n-1)*6), so:
(2n-1)*6
We multiply parentheses
12n-6
Back to the equation:
-(12n-6)
We get rid of parentheses
-12n+6
Back to the equation:
+(-12n+6)
We get rid of parentheses
n/()-12n+6=0
We multiply all the terms by the denominator
n-12n*()+6*()=0
We add all the numbers together, and all the variables
n-12n*()=0

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