(n+3)/6=(2n-1)/9

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Solution for (n+3)/6=(2n-1)/9 equation: 



(n+3)/6=(2n-1)/9

We move all terms to the left:

(n+3)/6-((2n-1)/9)=0

We calculate fractions


n/()+(-((2n-1)*6)/()=0



We calculate terms in parentheses: +(-((2n-1)*6)/(), so:

-((2n-1)*6)/(

We multiply all the terms by the denominator


-((2n-1)*6)



We calculate terms in parentheses: -((2n-1)*6), so:

(2n-1)*6

We multiply parentheses

12n-6

Back to the equation:

-(12n-6)



We get rid of parentheses

-12n+6

Back to the equation:

+(-12n+6)



We get rid of parentheses

n/()-12n+6=0

We multiply all the terms by the denominator


n-12n*()+6*()=0

We add all the numbers together, and all the variables

n-12n*()=0

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