(n+3)2=n2+32=n2+9

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Solution for (n+3)2=n2+32=n2+9 equation: 



(n+3)2=n2+32=n2+9

We move all terms to the left:

(n+3)2-(n2+32)=0

We add all the numbers together, and all the variables

-(+n^2+32)+(n+3)2=0

We multiply parentheses

-(+n^2+32)+2n+6=0

We get rid of parentheses

-n^2+2n-32+6=0

We add all the numbers together, and all the variables

-1n^2+2n-26=0

a = -1; b = 2; c = -26;
Δ = b2-4ac
Δ = 22-4·(-1)·(-26)
Δ = -100
Delta is less than zero, so there is no solution for the equation

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