(n+4)+(n+2)-n=51

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Solution for (n+4)+(n+2)-n=51 equation: 



(n+4)+(n+2)-n=51

We move all terms to the left:

(n+4)+(n+2)-n-(51)=0

We add all the numbers together, and all the variables

-1n+(n+4)+(n+2)-51=0

We get rid of parentheses

-1n+n+n+4+2-51=0

We add all the numbers together, and all the variables

n-45=0

We move all terms containing n to the left, all other terms to the right

n=45

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