(n+4)+n+(2n-10)=46

Solution for (n+4)+n+(2n-10)=46 equation:

Simplifying
(n + 4) + n + (2n + -10) = 46

Reorder the terms:
(4 + n) + n + (2n + -10) = 46

Remove parenthesis around (4 + n)
4 + n + n + (2n + -10) = 46

Reorder the terms:
4 + n + n + (-10 + 2n) = 46

Remove parenthesis around (-10 + 2n)
4 + n + n + -10 + 2n = 46

Reorder the terms:
4 + -10 + n + n + 2n = 46

Combine like terms: 4 + -10 = -6
-6 + n + n + 2n = 46

Combine like terms: n + n = 2n
-6 + 2n + 2n = 46

Combine like terms: 2n + 2n = 4n
-6 + 4n = 46

Solving
-6 + 4n = 46

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 4n = 46 + 6

Combine like terms: -6 + 6 = 0
0 + 4n = 46 + 6
4n = 46 + 6

Combine like terms: 46 + 6 = 52
4n = 52

Divide each side by '4'.
n = 13

Simplifying
n = 13