(n+4)-3n-(2-6c)=12

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Solution for (n+4)-3n-(2-6c)=12 equation:


Simplifying
(n + 4) + -3n + -1(2 + -6c) = 12

Reorder the terms:
(4 + n) + -3n + -1(2 + -6c) = 12

Remove parenthesis around (4 + n)
4 + n + -3n + -1(2 + -6c) = 12
4 + n + -3n + (2 * -1 + -6c * -1) = 12
4 + n + -3n + (-2 + 6c) = 12

Reorder the terms:
4 + -2 + 6c + n + -3n = 12

Combine like terms: 4 + -2 = 2
2 + 6c + n + -3n = 12

Combine like terms: n + -3n = -2n
2 + 6c + -2n = 12

Solving
2 + 6c + -2n = 12

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + 6c + -2 + -2n = 12 + -2

Reorder the terms:
2 + -2 + 6c + -2n = 12 + -2

Combine like terms: 2 + -2 = 0
0 + 6c + -2n = 12 + -2
6c + -2n = 12 + -2

Combine like terms: 12 + -2 = 10
6c + -2n = 10

Add '2n' to each side of the equation.
6c + -2n + 2n = 10 + 2n

Combine like terms: -2n + 2n = 0
6c + 0 = 10 + 2n
6c = 10 + 2n

Divide each side by '6'.
c = 1.666666667 + 0.3333333333n

Simplifying
c = 1.666666667 + 0.3333333333n

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