(n+4)=8-3(2n-8)

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Solution for (n+4)=8-3(2n-8) equation: 



(n+4)=8-3(2n-8)

We move all terms to the left:

(n+4)-(8-3(2n-8))=0

We get rid of parentheses

n-(8-3(2n-8))+4=0



We calculate terms in parentheses: -(8-3(2n-8)), so:

8-3(2n-8)

determiningTheFunctionDomain
-3(2n-8)+8

We multiply parentheses

-6n+24+8

We add all the numbers together, and all the variables

-6n+32

Back to the equation:

-(-6n+32)



We get rid of parentheses

n+6n-32+4=0

We add all the numbers together, and all the variables

7n-28=0

We move all terms containing n to the left, all other terms to the right

7n=28

n=28/7

n=4

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