(n+5)(n+2)=0

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Solution for (n+5)(n+2)=0 equation:


Simplifying
(n + 5)(n + 2) = 0

Reorder the terms:
(5 + n)(n + 2) = 0

Reorder the terms:
(5 + n)(2 + n) = 0

Multiply (5 + n) * (2 + n)
(5(2 + n) + n(2 + n)) = 0
((2 * 5 + n * 5) + n(2 + n)) = 0
((10 + 5n) + n(2 + n)) = 0
(10 + 5n + (2 * n + n * n)) = 0
(10 + 5n + (2n + n2)) = 0

Combine like terms: 5n + 2n = 7n
(10 + 7n + n2) = 0

Solving
10 + 7n + n2 = 0

Solving for variable 'n'.

Factor a trinomial.
(5 + n)(2 + n) = 0

Subproblem 1

Set the factor '(5 + n)' equal to zero and attempt to solve: Simplifying 5 + n = 0 Solving 5 + n = 0 Move all terms containing n to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + n = 0 + -5 Combine like terms: 5 + -5 = 0 0 + n = 0 + -5 n = 0 + -5 Combine like terms: 0 + -5 = -5 n = -5 Simplifying n = -5

Subproblem 2

Set the factor '(2 + n)' equal to zero and attempt to solve: Simplifying 2 + n = 0 Solving 2 + n = 0 Move all terms containing n to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + n = 0 + -2 Combine like terms: 2 + -2 = 0 0 + n = 0 + -2 n = 0 + -2 Combine like terms: 0 + -2 = -2 n = -2 Simplifying n = -2

Solution

n = {-5, -2}

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