(n+5)-(-2n+3)=(2n-5)+(n+4)

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Solution for (n+5)-(-2n+3)=(2n-5)+(n+4) equation: 



(n+5)-(-2n+3)=(2n-5)+(n+4)

We move all terms to the left:

(n+5)-(-2n+3)-((2n-5)+(n+4))=0

We get rid of parentheses

n+2n-((2n-5)+(n+4))+5-3=0



We calculate terms in parentheses: -((2n-5)+(n+4)), so:

(2n-5)+(n+4)

We get rid of parentheses

2n+n-5+4

We add all the numbers together, and all the variables

3n-1

Back to the equation:

-(3n-1)



We add all the numbers together, and all the variables

3n-(3n-1)+2=0

We get rid of parentheses

3n-3n+1+2=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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