(n+6)+n+(n-4)=35

Solution for (n+6)+n+(n-4)=35 equation:

Simplifying
(n + 6) + n + (n + -4) = 35

Reorder the terms:
(6 + n) + n + (n + -4) = 35

Remove parenthesis around (6 + n)
6 + n + n + (n + -4) = 35

Reorder the terms:
6 + n + n + (-4 + n) = 35

Remove parenthesis around (-4 + n)
6 + n + n + -4 + n = 35

Reorder the terms:
6 + -4 + n + n + n = 35

Combine like terms: 6 + -4 = 2
2 + n + n + n = 35

Combine like terms: n + n = 2n
2 + 2n + n = 35

Combine like terms: 2n + n = 3n
2 + 3n = 35

Solving
2 + 3n = 35

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 3n = 35 + -2

Combine like terms: 2 + -2 = 0
0 + 3n = 35 + -2
3n = 35 + -2

Combine like terms: 35 + -2 = 33
3n = 33

Divide each side by '3'.
n = 11

Simplifying
n = 11