(n+7)(n+2)=0

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Solution for (n+7)(n+2)=0 equation:


Simplifying
(n + 7)(n + 2) = 0

Reorder the terms:
(7 + n)(n + 2) = 0

Reorder the terms:
(7 + n)(2 + n) = 0

Multiply (7 + n) * (2 + n)
(7(2 + n) + n(2 + n)) = 0
((2 * 7 + n * 7) + n(2 + n)) = 0
((14 + 7n) + n(2 + n)) = 0
(14 + 7n + (2 * n + n * n)) = 0
(14 + 7n + (2n + n2)) = 0

Combine like terms: 7n + 2n = 9n
(14 + 9n + n2) = 0

Solving
14 + 9n + n2 = 0

Solving for variable 'n'.

Factor a trinomial.
(7 + n)(2 + n) = 0

Subproblem 1

Set the factor '(7 + n)' equal to zero and attempt to solve: Simplifying 7 + n = 0 Solving 7 + n = 0 Move all terms containing n to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + n = 0 + -7 Combine like terms: 7 + -7 = 0 0 + n = 0 + -7 n = 0 + -7 Combine like terms: 0 + -7 = -7 n = -7 Simplifying n = -7

Subproblem 2

Set the factor '(2 + n)' equal to zero and attempt to solve: Simplifying 2 + n = 0 Solving 2 + n = 0 Move all terms containing n to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + n = 0 + -2 Combine like terms: 2 + -2 = 0 0 + n = 0 + -2 n = 0 + -2 Combine like terms: 0 + -2 = -2 n = -2 Simplifying n = -2

Solution

n = {-7, -2}

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