(n+7)+(n+3)+(n+2)+n=

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Solution for (n+7)+(n+3)+(n+2)+n= equation:


Simplifying
(n + 7) + (n + 3) + (n + 2) + n = 0

Reorder the terms:
(7 + n) + (n + 3) + (n + 2) + n = 0

Remove parenthesis around (7 + n)
7 + n + (n + 3) + (n + 2) + n = 0

Reorder the terms:
7 + n + (3 + n) + (n + 2) + n = 0

Remove parenthesis around (3 + n)
7 + n + 3 + n + (n + 2) + n = 0

Reorder the terms:
7 + n + 3 + n + (2 + n) + n = 0

Remove parenthesis around (2 + n)
7 + n + 3 + n + 2 + n + n = 0

Reorder the terms:
7 + 3 + 2 + n + n + n + n = 0

Combine like terms: 7 + 3 = 10
10 + 2 + n + n + n + n = 0

Combine like terms: 10 + 2 = 12
12 + n + n + n + n = 0

Combine like terms: n + n = 2n
12 + 2n + n + n = 0

Combine like terms: 2n + n = 3n
12 + 3n + n = 0

Combine like terms: 3n + n = 4n
12 + 4n = 0

Solving
12 + 4n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 4n = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 4n = 0 + -12
4n = 0 + -12

Combine like terms: 0 + -12 = -12
4n = -12

Divide each side by '4'.
n = -3

Simplifying
n = -3

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