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(n+8)(8n+1)=0
We multiply parentheses ..
(+8n^2+n+64n+8)=0
We get rid of parentheses
8n^2+n+64n+8=0
We add all the numbers together, and all the variables
8n^2+65n+8=0
a = 8; b = 65; c = +8;
Δ = b2-4ac
Δ = 652-4·8·8
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-63}{2*8}=\frac{-128}{16} =-8 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+63}{2*8}=\frac{-2}{16} =-1/8 $
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